What is the final velocity of an electron accelerating through a potential of 1600 V, if its initial velocity is zero.

2.37

\times

^{7}

m s

^{- 1}

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2.37

\times

^{8}

m s

^{- 1}

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2.37

\times

^{6}

m s

^{- 1}

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2.37

\times

^{5}

m s

^{- 1}

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Solution

The correct option is C 2.37 $\times$ 10 $^{7}$ m s $^{- 1}$
As we know,
$\frac{1}{2}$ mv $^{2} = e V$
$v = \sqrt{\frac{2 e V}{m}}$ $= \sqrt{[\frac{2 \times 1.6 \times 10^{- 19} \times 1600}{9.1 \times 10^{- 31}}]}$
$v = 2.37$ $\times$ $10^{7}$ m/s.

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