Question

# What is the formula of compound in which the element $$Y$$ forms $$ccp$$ lattice and atoms of $$X$$ occupy $$2/3^{rd}$$ of tetrahedral voids?

Solution

## Effective no of atoms forming ccp is $$X= 4$$.Effective number of tetrahedral holes in ccp is $$Y=8$$.So,$$8\times 2/3 = 16/3$$$$X:Y$$$$=4:16/3$$$$=12:16$$$$=3:4$$So, the formula is $$X_4Y_3$$.Chemistry

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