What is the formula of compound in which the element $Y$ forms $c c p$ lattice and atoms of $X$ occupy $2 / 3^{r d}$ of tetrahedral voids?

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Solution

Effective no of atoms forming ccp is $X = 4$ .

Effective number of tetrahedral holes in ccp is $Y = 8$ .

So,
$8 \times 2 / 3 = 16 / 3$

$X : Y$ $= 4 : 16 / 3$ $= 12 : 16$ $= 3 : 4$

So, the formula is $X_{4} Y_{3}$ .

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