What is the magnification in the given diagram?

Given, OA = 10 cm and O’A’ = 2 cm

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-2

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- 0.2

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- 10

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Solution

The correct option is C - 0.2

Height of the object, $h_{o} =$ 10 cm
Height of the image, $h_{i} =$ – 2 cm
Magnification = $\frac{h_{i}}{h_{o}} = \frac{- 2}{10} = - 0.2$
The negative sign indicates that the image formed is real.

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