Question

What is the mass of a computer chip containing $1.20\times {10}^{23}$ atoms of silicon?

• A. $6.02\times {10}^{23}$ grams
• B. 5.6 grams
• C. 28 grams
• D. 14 grams
• E. 2 grams

Answer 1

The correct option is B 5.6 grams

One mole of silicon $=28g$ (atomic mass of silicon)

Now, number of atoms in one mole (or $28g$) of silicon $=6.02\times {10}^{23}$, or we can say $6.02\times {10}^{23}$ atoms are present in $28g$

Therefore, $1.20\times {10}^{23}$ atoms will be present in $=28\times 1.20\times {10}^{23}/6.02\times {10}^{23}=5.6g$