Question

What is the maximum value of the force F such that the block shown in the arrangement, does not move?

• A. 20 N
• B. 10 N
• C. 12 N
• D. 15 N

Answer 1

The correct option is A

20 N

For vertical equilibrium, $N=mg+Fsin{60}^{\circ }=\sqrt{3}(10+\frac{F}{2})$
For horizontal equilibrium, $Fcos{60}^{\circ }=\mu N\Rightarrow \frac{F}{2}=\frac{1}{2\sqrt{3}}\times \sqrt{3}(10+\frac{F}{2})$
Solving we get, F = 20 N