Question

What is the minimum quantity of methyl iodide required for preparing one mole of ethane by Wurtz reaction ?(At.wt.of iodine=127)

• A. 142 gram
• B. 568 gram
• C. 326 gram
• D. 284 gram

Answer 1

The correct option is D 284 gram

In Wurtz reaction, two moles of alkyl halide reacts with sodium metal to form one mole of higher alkane.

Given reaction,

$2C{H}_{3}I+2Na\to C{H}_3-C{H}_3+2NaI$

Molecular weight of methyl iodide $=127+15=142$ gm

Hence, the minimum quantity of methyl iodide required$=2\times 142=284$ gm.

Hence, option $D$ is correct.