What is the minimum value of x which satisfies the inequation (3)2<(−3)x ?
4
In the given inequation, LHS is positive.
We need to find the value of x such that LHS <RHS
If the exponent of a negative number is even, then the resulting number is always positive.
RHS is positive only when x is even.
So, the minimum value of x should be an even number greater than 2, which is 4.