What is the momentum of a body of mass 100 g having a K.E. of 20 J?

2 k g m s^{- 1}

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\frac{1}{2} k g m s^{- 1}

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2 g c m s^{- 1}

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None of these

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Solution

The correct option is A $2 k g m s^{- 1}$
We know that the Kinetic energy of a body is $E_{k} = \frac{1}{2} m v^{2}$ and Momentum $p = m v$
$E_{k} = \frac{p^{2}}{2 m}$ or $p = \sqrt{2 m E_{k}}$

Substituting the given values, we have $p = \sqrt{2 \times 100 \times 10^{- 3} \times 20}$
$p = \sqrt{4} = 2$
The momentum of the body $= 2 k g m s^{- 1}$

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What is the momentum of a body of mass 100 g having a K.E. of 20 J?

The correct option is A 2kgms−1We know that the Kinetic energy of a body is Ek=12mv2 and Momentum p=mvEk=p22m or p=√2mEkSubstituting the given values, we have p=√2×100×10−3×20p=√4=2The momentum of the body =2kgms−1