What is the number of valence electron in
(a) Sodium ion $({N a}^{+})$
(b) Oxide ion $(O^{2 -})$
(Atomic number of Na=11; 0=8)

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Solution

(a) $N a^{+}$ has $10$ electrons
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{o}$
Its octet is complete so number of valence electrons is zero.
(b) Oxide ion $(O^{2 -})$
$1 s^{2} 2 s^{2} 2 p^{6}$
Octet is complete, so no valence electron.

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What is the number of valence electron in (a) Sodium ion (Na+)(b) Oxide ion(O2−)(Atomic number of Na=11; 0=8)

(a) Na+ has 10 electrons1s22s22p63soIts octet is complete so number of valence electrons is zero.(b) Oxide ion (O2−)1s22s22p6Octet is complete, so no valence electron.

What is the number of valence electron in
(a) Sodium ion $({N a}^{+})$
(b) Oxide ion $(O^{2 -})$
(Atomic number of Na=11; 0=8)

(a) $N a^{+}$ has $10$ electrons
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{o}$
Its octet is complete so number of valence electrons is zero.
(b) Oxide ion $(O^{2 -})$
$1 s^{2} 2 s^{2} 2 p^{6}$
Octet is complete, so no valence electron.