Question

# What is the order of stability of $$N_2$$ and its ions?

A
N2>N+2=N2>N22
B
N+2>N2>N2>N22
C
N2>N+2>N2>N22
D
N22>N2=N+2>N2

Solution

## The correct option is A $$N_2 > N_2^+ = N_2^- > N_2^{2-}$$Stability of a molecule is related with bond order like this:-$$Stability\quad \alpha \quad Bond\quad order$$and to calculate bond order, formula is = $$\frac { Number\quad of\quad electrons\quad in\quad BMO\quad -\quad Number\quad of\quad electrons\quad in\quad ABMO }{ 2 }$$$$N_2$$ has highest bond order So the correct option is [A]Chemistry

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