Question

# What is the oxidation number of $\mathrm{N}$ in $\mathrm{NO}$?

Open in App
Solution

## Oxidation number: Oxidation number denotes the oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belongs entirely to a more electronegative element.Calculating the oxidation number of Nitrogen(N) in $\mathrm{NO}$:The oxidation state of Oxygen(O) = -2Consider the oxidation state of nitrogen(N) = xNow, $x-2=0\phantom{\rule{0ex}{0ex}}x=+2$Hence, the oxidation number of $\mathrm{N}$ in $\mathrm{NO}$ is $+2$.

Suggest Corrections
4