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Question

What is the oxidation number of underlined element?

    $$Ba(H_2\underline {P}O_2)_2$$


Solution

Let $$x$$ be the oxidation number of P in $$Ba(H_2\underline {P}O_2)_2$$.
Since the overall charge on the compound is $$0$$, the sum of oxidation states of all elements in it should be equal to $$0$$.
Therefore, $$2+2(2(1)+x +2(-2)) =0$$
or, $$x=+1$$
Hence, the oxidation number of P in $$Ba {(H_2}\underline {P}O_2)_2$$ is $$+1$$.

Chemistry

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