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Question

What is the oxidation number of underlined element?

Ba(H2PO2)2

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Solution

Let x be the oxidation number of P in Ba(H2PO2)2.
Since the overall charge on the compound is 0, the sum of oxidation states of all elements in it should be equal to 0.
Therefore, 2+2(2(1)+x+2(2))=0
or, x=+1
Hence, the oxidation number of P in Ba(H2PO2)2 is +1.

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