Question

# What is the oxidation number of underlined element?    $$Ba(H_2\underline {P}O_2)_2$$

Solution

## Let $$x$$ be the oxidation number of P in $$Ba(H_2\underline {P}O_2)_2$$.Since the overall charge on the compound is $$0$$, the sum of oxidation states of all elements in it should be equal to $$0$$.Therefore, $$2+2(2(1)+x +2(-2)) =0$$or, $$x=+1$$Hence, the oxidation number of P in $$Ba {(H_2}\underline {P}O_2)_2$$ is $$+1$$.Chemistry

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