Question

# What is the percentage of persons who read only A but neither B nor C ?

A
4%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C 1%Let total numbers of people be 100, So for newspapersn(A)=42,n(B)=51,n(C)=68,n(A∩B)=30n(B∩C)=28n(A∩C)=36Also given, n(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A∪B∪C)=8n(A∪B∪C)=100−n(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A∪B∪C)=100−8=92Also,n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)92=42+51+68−30−28−36+n(A∩B∩C)n(A∩B∩C)=25Now for people who read only A but neither B or C =n(A)−n(A∩B)−n(A∩C)+n(A∩B∩C)=42−30−36+25=1Hence, C is correct.

Suggest Corrections
0
Join BYJU'S Learning Program
Select...
Related Videos
Operations on Sets
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program
Select...