Question

What is the perimeter of the square inscribed in a circle of radius 8 cm?

• A. $38\sqrt{2}cm$
• B. $36\sqrt{2}cm$
• C. $34\sqrt{2}cm$
• D. $32\sqrt{2}cm$

Answer 1

The correct option is D $32\sqrt{2}cm$


Given: radius of circle = 8cm
$\therefore$ Diameter of circle = 16cm
Let the side of square = s cm
Using Pythagors theorem,
$s^2+s^2=(16{)}^2⟹2s^2=256⟹s^2=128⟹s=8\sqrt{2}$
$\therefore \text{Perimeter of square}=4\times 8\sqrt{2}=32\sqrt{2}cm$