What is the probability of getting a sum 9 from two throws of a dice?

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Solution

The correct option is C
Total output from throwing two dice - 6 $\times$ 6=36 ways
Required output of sum 9-{(3,6),(6,3),(5,4),(4,5)}
Total required ways = 4 ways
Required probability = $\frac{4}{36} = \frac{1}{9}$

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