Question

What is the probability that there are 53 Sundays in a leap year?

• A. $\frac{1}{6}$
• B. $\frac{2}{7}$
• C. $\frac{3}{8}$
• D. $\frac{4}{9}$

Answer 1

The correct option is B $\frac{2}{7}$

In a leap year, there are 366 days.
366 days = 52 complete weeks + 2 days = 52 Sundays + 2 days

The 2 days can be as follows
$\begin{array}{ccc}\left(1\right)& Sun& Mon\\ \left(2\right)& Mon& Tue\\ \left(3\right)& Tue& Wed\\ \left(4\right)& Wed& Thu\\ \left(5\right)& Thu& Fri\\ \left(6\right)& Fri& Sat\\ \left(7\right)& Sat& Sun\end{array}$

So, ${53}^{rd}$ Sunday can happen in 2 ways out of all the 7 possible ways.

$\therefore$ Required probability =$\frac{2}{7}$