Question

What is the ratio whose terms differ by 40 and the measure of which is $\frac{2}{7}$?

• A. 16 : 56
• B. 14 : 56
• C. 15 : 56
• D. 16 : 72

Answer 1

The correct option is A 16 : 56

Let ratio be x and x+40
then $\frac{x}{x+40}=\frac{2}{7}$
$\Rightarrow 7x=2(x+40$
$\Rightarrow 7x=2x+80$
$\Rightarrow 5x=80$
$\Rightarrow x=16$
Required Ratio=$16:56$