What is the relative humidity of air at $1$ bar pressure and $313 K$ temperature if partial pressure of water in air is $19.355 m m H g$ for any data use the table given below:
(in mmHg) V.P. of $H_{2} O$ 25.2 31.8 42.2 55.3 71.9 92.5
(in K) Temp. 298 303 308 313 318 323

35 %

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25 %

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75 %

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5 %

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Solution

The correct option is A $35 %$
$Relative humidity = (\frac{partial pressure of water}{vapour pressure of water} \times 100) %$
$= (\frac{19.355}{55.3} \times 100)$
$= 35 %$

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(in mmHg)	V.P. of $H_{2} O$	25.2	31.8	42.2	55.3	71.9	92.5
(in K)	Temp.	298	303	308	313	318	323

What is the relative humidity of air at 1 bar pressure and 313K temperature if partial pressure of water in air is 19.355mmHg for any data use the table given below:(in mmHg)V.P. of H2O25.231.842.255.371.992.5(in K)Temp.298303308313318323

The correct option is A 35%Relative humidity=(partial pressure of watervapour pressure of water×100)%=(19.35555.3×100)=35%

What is the relative humidity of air at $1$ bar pressure and $313 K$ temperature if partial pressure of water in air is $19.355 m m H g$ for any data use the table given below:
(in mmHg) V.P. of $H_{2} O$ 25.2 31.8 42.2 55.3 71.9 92.5
(in K) Temp. 298 303 308 313 318 323

The correct option is A $35 %$
$Relative humidity = (\frac{partial pressure of water}{vapour pressure of water} \times 100) %$
$= (\frac{19.355}{55.3} \times 100)$
$= 35 %$