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Question

What is the rms speed of a gas molecule of mass 10−12 gm at room temperature 27o according to kinetic theory of gases?

A
0.35 cm/sec
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B
2.03×102 m/sec
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C
0.70 m/sec
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D
0.35 m/sec
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Solution

The correct option is A 0.35 cm/sec
According to the problem:
let m be the mass than 12mu2 is kinetic energy of this partical where, rms velocity
hence, the kinetic energy of molecule =3RT2×N
SINCE, =12MU2=3RT2N U=[3RN×TM]
Given:
m=1012g
R=8.314×107ergandt=300k
that =3×8.314×107×3006.023×1023×1012
u=0.35cmsec1

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