What is the smallest 5-digit number divisible by 11 and containing each of the digits 2, 3, 4, 5, 6?
Consider the number 24365 formed by the digits 2, 3, 4, 5 and 6
Here, 2 − 4 + 3 − 6 + 5 = 0
Thus, 24365 is the smallest number divisible by 11.
How many 5-digit numbers divisible by 11 are there containing each of the digits 2, 3, 4, 5, 6?
A number when divided by 3,4,5,6,7 gives remainders 2,3,4,5,6 respectively. The smallest such 5 digit number is?