Question

What is the smallest number that, when divided by 35, 56 and 91 leaves remainders of 7 in each case?

Answer 1

TO FIND: Smallest number that, when divided by 35, 56 and 91 leaves remainder of 7 in each case

L.C.M OF 35, 56 and 91

Hence 84 is the least number which exactly divides 28, 42 and 84 i.e. we will get a remainder of 0 in this case. But we need the smallest number that, when divided by 35, 56 and 91 leaves remainder of 7 in each case

Therefore

Hence is smallest number that, when divided by 35, 56 and 91 leaves remainder of 7 in each case.