CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29 and 34 respectively?

A
1404
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1394
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1606
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1406
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1394

L.C.M = 5 × 2 × 2 × 5 × 7 × 2
= 1400
Given, the smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29 and 34 respectively.
20 - 14 = 25 - 19 = 35 - 29 = 40 - 34 = 6
Here, the difference is equal. So, 6 should be subtracted from the LCM to get the number.
The smallest number =L.C.M6
=14006=1394

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Special Factors and Multiples
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon