Question

What is the square root of $3$ plus the square root of $27$?

Answer 1

Ans $4\sqrt{3}$

Explanation:

simplifying $\sqrt{27}$ by prime factorisation:

$\sqrt{27}=\sqrt{3\times 3\times 3}=\sqrt{3^2\times 3}=3\sqrt{3}$

The expression can now be expressed as

$\sqrt{3}+\sqrt{27}=\sqrt{3}+3\sqrt{3}$

$=4\sqrt{3}$