What is the value of ${((2)^{- 1})}^{- 2}$ ?

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Solution

$2^{- 1}$ = $\frac{1}{2}$
${((2)^{- 1})}^{- 2}$ = $(\frac{1}{2})^{- 2}$ = ${(\frac{1}{(\frac{1}{2})})}^{2}$ = $(\frac{2}{1})^{2}$ = $2^{2}$ = 4

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Similar questions

What is the value of ${((2)^{- 1})}^{- 2}$ ?

\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + . . . . . . . + \frac{1}{\sqrt{15} + \sqrt{2}}

(2 + 1) (2^{2} + 1) (2^{4} + 1) (2^{8} + 1)

\frac{1}{1 + \sqrt{2} + \sqrt{3}} + \frac{1}{1 - \sqrt{2} + \sqrt{3}}

W^{- 2}

W^{- 1} = \frac{1}{2}

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