What is the value of x + y + z , if x+10°, y + 22° and z + 34° are the interior angles of a triangle?
A
114°
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B
246°
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C
66°
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D
180°
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Solution
The correct option is A 114° We know that the sum of interior angles in a triangle is 180°.
So, if x+10°, y + 22° and z + 34° are the angles of a triangle, then
x+10° + y + 22° + z + 34° = 180°
x+y+z+(10+22+34) = 180°
x+y+z = 180° - 66°
x+y+z = 114°.