Question

What is the vertex of the quadratic function y = $x^2-6x+12$?

• A. (1, 1)
• B. (2, 2)
• C. (2, 3)
• D. (3, 3)

Answer 1

The correct option is D

(3, 3)

We saw that the vertex of the parabola or quadratic function $y-k=S(x-h{)}^2$ is (h,k). So we will try to express the given quadratic in this form. Y = $x^2$ - 6x + 12 can be expressed as
$y=(x-3{)}^2+3$
$\Rightarrow y-3=(x-3{)}^2$
Comparing it with $y-k=s(x-h{)}^2$ we get
h = 3 and y = 3
So the vertex is (3,3)