Question

# What is the volume of $$O_2$$ liberated at anode at STP in the electrolysis of $$CdSO_4$$ solution when a current of 2 A is passed for 8 min?

Solution

## $$v = 2A$$ ,   $$t = 480sec$$$$Q= i.t = (2\times480) coulomb$$Number of faraday $$= \left( \cfrac { 960 }{ 96500 } \right) =9.94\times10^{-3}F$$Since 1F produces 5.6litre of $$O_2$$ at STP$$\therefore 9.94\times15^3 F$$ produces $$\left(5.6\times9.94\times10^{-3}\right)$$ litre                                            $$= 0.056\quad litre$$Chemistry

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