Question

What mass (in kg) of $K_{2}O$ contains the same number of moles of $K$ atoms as $1kg$ $KCl$?

• A. $0.158kg$
• B. $0.315kg$
• C. $1.262kg$
• D. $0.631kg$

Answer 1

Answer: (D)

$0.631kg$

Let the mass of $K_{2}O=xgm$.

$\frac{x}{94}$ mol $K_{2}O=\frac{2x}{94}$ mol $K^{+}$
$1000g$ $KCl=\frac{1000}{74.5}$ mol $KCl$

$\therefore \frac{2x}{94}=\frac{1000}{74.5}$
$x=631$ gm $=0.631$ kg.

Hence, option D is correct.