CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

What mass of $$HNO_3$$ is needed to convert $$5\:g$$ of iodine into iodic acid according to the reaction?
$$I_2+HNO_3\longrightarrow HIO_3+NO_2+H_2O$$


A
12.4g
loader
B
24.8g
loader
C
0.248g
loader
D
49.6g
loader

Solution

The correct option is B $$12.4\:g$$
$$I_2+HNO_3\longrightarrow HIO_3+NO_2+H_2O$$
   0    +5                    +5         +4
At equivalent point,
$$N_1V_1 = N_2V_2$$
$$5*10/254 = m/63; \ m = 12.4$$ gm.

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image