What must be added to nbsp-x-3-3x-8- to get -3x-3-x-2-6-2x-3-x-2-3x-17-2x-3-x-2-3x-14-2x-3-x-2-x-14-2x-3-4x-2-3x-14-

The correct option is B 2x^3+x^2 3x+14 Let the expression to be added be nbsp;y. (x^3+3x 8)+y= 3x^3+x^2+6 ⇒ y=(3x^3+x^2+6 ) (x^3+3x 8) nbsp; 3x^3+x^2 ...

Byju's Answer

Standard VIII

Mathematics

Addition and Subtraction of Algebraic Expression

What must be ...

Question

What must be added to $(x^{3} + 3 x - 8)$ to get $(3 x^{3} + x^{2} + 6)$ ?

$2 x^{3} + x^{2} - 3 x + 17$

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$2 x^{3} + x^{2} - 3 x + 14$

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$2 x^{3} + x^{2} - x + 14$

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$2 x^{3} + 4 x^{2} - 3 x + 14$

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Solution

The correct option is B
$2 x^{3} + x^{2} - 3 x + 14$

Let the expression to be added be $y$ .

$(x^{3} + 3 x - 8) + y = 3 x^{3} + x^{2} + 6 \Rightarrow y = (3 x^{3} + x^{2} + 6) - (x^{3} + 3 x - 8)$

$3 x^{3} + x^{2} + 6$
$x^{3} + 3 x - 8$
$- - + - --------------- -$
$2 x^{3} + x^{2} - 3 x + 14$

So we have to add $(2 x^{3} + x^{2} - 3 x + 14)$ to $(x^{3} + 3 x - 8)$ , to get the expression $(3 x^{3} + x^{2} + 6)$ .

Suggest Corrections

What must be added to (x3+3x−8) to get (3x3+x2+6)?

What must be added to $(x^{3} + 3 x - 8)$ to get $(3 x^{3} + x^{2} + 6)$ ?