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Question

What must be subtracted from polynomial f(x)=x4+2x313x212x+21 so that the resulting polynomial is exactly divisible by x24x+3 ?

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Solution

Any division statement can be rewritten in the form of
Dividend = Divisor x Quotient + Remainder.
When the remainder is zero, the dividend is said to be the multiple of the divisor.

When the remainder is not equal to zero, and if it is subtracted from the dividend, then the dividend would become a multiple of the divisor.

Dividend = x to the power of 4 plus 2 x cubed minus 13 x squared minus 12 x plus 21
Divisor = x squared minus 4 x plus 3

Step 1: Divide the dividend by divisor

x squared minus 4 x plus 3 ) x to the power of 4 plus 2 x cubed minus 13 x squared minus 12 x plus 21 ( x squared plus 6 x plus 8
x to the power of 4 minus 4 x cubed plus 3 x squared
-___+____-___
6 x cubed minus 16 x squared minus 12 x
6 x cubed minus 24 x squared plus 18 x
-____+_____-____
8 x squared minus 30 x plus 21
8 x squared minus 32 x plus 24
-____+____-____
2 x minus 3


Quotient = x squared plus 6 x plus 8
Remainder = 2 x minus 3

Hence, on subtracting 2x – 3 from the dividend, it will be exactly divisible by the given divisor.

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