Question

What number should divide $-\frac{33}{16}$ to get $-\frac{11}{4}$?

Answer 1

Let the required number be $x$.

According to the question,

$\frac{-33}{16}÷x=\frac{-11}{4}$

$⟹\frac{-33}{16}\times \frac{1}{x}=\frac{-11}{4}$

$⟹\frac{-33}{16x}=\frac{-11}{4}$

$⟹16x\times -11=4\times -33$
$⟹-176x=-132$
$⟹\frac{-176x}{-176}=\frac{-132}{-176}$
$⟹x=\frac{3}{4}$

Hence, the required number is $\frac{3}{4}$.