CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What quantity must be added to each term of the ratio 7:13 so as to make it equal to 9:11


A

21

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

20

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

19

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

18

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

20


Let x be the quantity to be added to each term in the ratio 7:13.

The resultant ratio is equal to 9:11.

So we have,

7+x13+x=911

ie. 11(7+x) = 9(13+x)

77 + 11x = 117 + 9x

11x - 9x = 117 - 77

2x = 40

x = 20

So the quantity that should be added to the initial ratio is 20.

Verification: LHS = 7+2013+20=2733 =911 = RHS


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ratio
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon