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Question

What quantity of energy is required to convert 2kg of water at 20oC into vaour at 100oC? (L=2.3×103kJkg1).

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Solution

To find the quantity of heat is required to transform 2kg of water at 20C into vapour at 100C.
Solution:
We know,
Specific heat of water, s=4.18J/(gC)
Enthalpy of vapourization, L=2.3×103kJ/kg=2300J/g
As per the given condition,
Mass of water, m=2kg=2×103g
The total heat required will be sum of heat required to to warm the water from 20.0°C to 100.0°C plus heat required to vapourize the water to steam at 100°C
qtotal=q1+q2qtotal=ms(ΔT)+mLqtotal=2×103×4.18(10020)+2×103×2300qtotal=668.8×103+4600×103qtotal=5268.6×103J=5269kJ
is the quantity of heat is required to transform 2kg of water at 20C into vapour at 100C.

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