Question

What should be added to $\frac{-3}{8}$ to get $\frac{5}{12}$?

Answer 1

Let the required number be x.

$\begin{array}{l}\frac{\begin{array}{l}\\ -3\end{array}}{8}+x=\frac{5}{12}\\ =>x=\frac{5}{12}-\frac{(-3)}{8}\\ =>x=\frac{10+9}{24}\\ =>x=\frac{19}{24}\\ \text{Hence, the required number is}\frac{19}{24}\text{.}\\ \end{array}$