Question

What should be added to $6\frac{7}{15}$ to get $8\frac{1}{5}$

Answer 1

Let us assume, if we add ${}^{\prime }{x}^{\prime }$ to $6\frac{7}{15}$ we would get $8\frac{1}{5}$
So by the condition, we get

$6\frac{7}{15}+x=8\frac{1}{5}$

$\Rightarrow x=(8\frac{1}{5}-6\frac{7}{15})$

$\Rightarrow x=(\frac{41}{5}-\frac{97}{15})$

$\Rightarrow x=(\frac{41\times 3}{5\times 3}-\frac{97}{15})$

$\Rightarrow x=\left(\frac{123-97}{15}\right)$

$\therefore x=\frac{26}{15}$