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Question

What should be added to each of the numbers 13, 17 and 22 so that, the resulting numbers are in continued proportion?
  1. 3

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Solution

The correct option is A 3
Let the required number to be added is x

13 + x, 17 + x and 22 + x are in continued proportion.

13+x17+x=17+x22+x

(13+x)(22+x)=(17+x)2 [Cross multiplication]

286+35x+x2=289+34x+x2

35x34x=289286

x=3

The number to be added is 3.

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