Question

# What should be the acceleration a of the box shown in Fig. 5.54 so that the block of mass m exerts a force $$\displaystyle \frac{mg}{4}$$  on the floor of the box?

A
3g4
B
5g4
C
3g2
D
g2

Solution

## The correct option is A $$\displaystyle \frac{3g}{4}$$Let box is accelerated downward with acceleration '$$a$$' so from the FBD of the block,$$\therefore$$  $$mg- N =ma$$$$N= \dfrac{mg}{4}$$ is given$$\Rightarrow mg-\dfrac{mg}{4}=ma$$$$\Rightarrow \dfrac{3mg}{4}=ma$$$$\Rightarrow a= \dfrac{3g}{4}$$Physics

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