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Question

What should be the acceleration a of the box shown in Fig. 5.54 so that the block of mass m exerts a force $$\displaystyle \frac{mg}{4}$$  on the floor of the box?

239935_7d9288a8d8f440e4b42c54355e3f8b60.png


A
3g4
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B
5g4
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C
3g2
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D
g2
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Solution

The correct option is A $$\displaystyle \frac{3g}{4}$$
Let box is accelerated downward with acceleration '$$a$$' so from the FBD of the block,
$$\therefore$$  $$  mg- N =ma$$
$$N= \dfrac{mg}{4}$$ is given
$$\Rightarrow mg-\dfrac{mg}{4}=ma$$
$$\Rightarrow \dfrac{3mg}{4}=ma$$
$$\Rightarrow a= \dfrac{3g}{4}$$


924750_239935_ans_6c14f968ae7544e4b119cbb5b426915b.png

Physics

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