Question

# What should be the magnitude and direction of electric field?

A
7Nc1, Vertically up to velocity
B
7Nc1, horizontally and to velocity
C
14Nc1, horizontally parallel to velocity
D
none of these

Solution

## The correct option is A $$7 Nc^{-1}$$, horizontally and $$\perp$$ to velocity$$\vec v\times \vec B=E$$If angle between B and v is $$\dfrac{\pi}{2}$$$$v$$ = $$\displaystyle \dfrac{E}{B}$$or $$vB$$ = $$14(0.5)$$ = $$7 NC^{-1}$$Thus magnitude of electric field is 7 and direction is horizontal, perpendicular to velocityPhysics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More