CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

What should be the magnitude and direction of electric field?


A
7Nc1, Vertically up to velocity
loader
B
7Nc1, horizontally and to velocity
loader
C
14Nc1, horizontally parallel to velocity
loader
D
none of these
loader

Solution

The correct option is A $$7 Nc^{-1}$$, horizontally and $$\perp$$ to velocity
$$\vec v\times \vec B=E$$
If angle between B and v is $$\dfrac{\pi}{2}$$
$$v$$ = $$\displaystyle \dfrac{E}{B}$$
or $$vB$$ = $$14(0.5)$$ = $$7 NC^{-1}$$
Thus magnitude of electric field is 7 and direction is horizontal, perpendicular to velocity

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image