CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

What volume of $$0.200\ M\ NaOH$$ is needed to react completely with $$2.54\ g$$ iodine according to the equation:
$$3I_{2} + 6NaOH \rightarrow 5NaI + NaIO_{3} + 3H_{2}O$$


A
100.0mL
loader
B
40.0mL
loader
C
4.00mL
loader
D
2.00mL
loader

Solution

The correct option is A $$100.0 mL$$

No. of moles of iodine = wt. of iodine/ its molar mass.

no.of moles of iodine = 2.54 / 254 = 0.01 mol.

According to the given equation, NaOH reacts with I₂ in 2 : 1 ratio. 

No. of moles go NaOH = 0.01 x 2 = 0.02 mol

We know that, Molarity = no. of moles of solute / Vol. of solution (in L)

Vol. of solution = no. of moles (of NaOH) / Molarity 

Vol. of solution = 0.02 / 0.2 = 0.1 L or 100 mL.

Hence, option A is correct.


Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image