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Question

What volume of 0.200 M NaOH is needed to react completely with 2.54 g iodine according to the equation:
3I2+6NaOH5NaI+NaIO3+3H2O

A
100.0mL
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B
40.0mL
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C
4.00mL
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D
2.00mL
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Solution

The correct option is A 100.0mL

No. of moles of iodine = wt. of iodine/ its molar mass.

no.of moles of iodine = 2.54 / 254 = 0.01 mol.

According to the given equation, NaOH reacts with I₂ in 2 : 1 ratio.

No. of moles go NaOH = 0.01 x 2 = 0.02 mol

We know that, Molarity = no. of moles of solute / Vol. of solution (in L)

Vol. of solution = no. of moles (of NaOH) / Molarity

Vol. of solution = 0.02 / 0.2 = 0.1 L or 100 mL.

Hence, option A is correct.


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