You visited us 1 times! Enjoying our articles? Unlock Full Access!

Volume of Gases and Number of Moles

What volume o...

Question

What volume of $2 M H_{2} S O_{4}$ is required to form 0.2 N of 100 mL of solution?

5 m L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $5 m L$
1 M $H_{2} S O_{4}$ corresponds to 2 N $H_{2} S O_{4}$ .

0.2 N $H_{2} S O_{4}$ corresponds to 0.1 M $H_{2} S O_{4}$ .

$M_{1} V_{1} = M_{2} V_{2}$

$2 M \times V_{1} = 0.1 M \times 0.1 L$ (as 100 mL = 0.1 L)

$V_{1} = 0.005 L = 5 m L$

Hence, 5 mL of 2 M $H_{2} S O_{4}$ is required

Suggest Corrections

Similar questions

50 m l

3.50 M H_{2} S

2 M H_{2} S O_{4}

(5 m l)

X

y m l

1 M N a O H

(y m l)

1 M N a O H

10 m l

0.6 M

H_{2} {S O}_{4}

(N)

X

N a_{2} C O_{3}

N a_{2} C O_{3}

p O H = p K_{b} (N H_{3})

0.2 N N a O H

20 mL

0.1 N H_{2} S O_{4}

20 mL

0.1 N H C l

Join BYJU'S Learning Program