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Question

What volume of ccl4 (d= 1.6g/cc) contain 6.02*10^25 ccl4 molecules?

A. 10.5L

B. 250ml

C. 9.625L

D. 1.712L


Solution

Let us say V (in cc) volume of CCl4 (d= 1.6g/cc) contain 6.02*10^25 ccl4 molecules
Total mass of V volume of CCl4 = 1.6 V
Molecular mass of CCl4 = 12 + 4*(35.5) = 154
No. of moles in V volume = 1.6 V /154
No. of molecules = 1.6 V/154 * 6.02 *10^23
6.02 * 10^25 = 1.6 V/154 * 6.02 *10^23
V = 100 * 154 /1.6 = 9625 cc
V = 9.625 litre
Hence option (C) is correct.

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