What volume of oxygen gas $(O_{2})$ measured at $0^{\circ} C$ and 1 atm is needed to burn completely one litre of propane gas $(C_{3} H_{8})$ measured under the same conditions?

Open in App

Solution

The balanced chemical equation for the complete combustion of propane is given as :
$C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 C O_{2} (g) + 4 H_{2} O$
Hence, as per the Gay lussac's law, volume of oxygen gas measured at $0^{\circ} C$ and 1 atm needed to burn compeletely $1 L$ of propane gas $(C_{3} H_{8})$ under the same conditions is $5 L$ .

Hence the correct answer is option (a).

Suggest Corrections

Similar questions

(O_{2})

0^{\circ} C

(C_{3} H_{8})

(O_{2})

0^{0}

(C_{3} H_{8})

O_{2}

0^{o} C

(C_{3} H_{8})

what volume of oxygen gas measured at 0 C and 1 atm, is needed to burn completely 1L of propane gas measured under the same conditions?

Join BYJU'S Learning Program