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Question

# What volume of water must be added to a solution of 250 mL of a 6 M HCl solution and 650 mL of a 3 M HCl solution to obtain a 3 M resultant solution?

A
60 mL
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B
350 mL
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C
250 mL
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D
500 mL
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Solution

## The correct option is C 250 mLWhen two solutions are mixed to form a solution, M1V1+M2V2=M×V Where M1 and M2 are the concentrations of the given HCl solutions and V1 and V2 are their respective volumes. M1=6 M,M2=3 M,V1=250 mL,V2=650 mL M and V are the molarity and volume of the final solution, respectively. (250×6)+(650×3)=3×V ⇒V=1150 mL V1+V2=(250+650) mL = 900 mL Therefore, 1150 – 900 = 250 mL of water should be added to obtain a 3 M resultant solution.

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