What was the average speed of the cyclist for the past hour when he travels at a constant $25 k m / h r$ for $30$ minutes, coasts for $15$ minutes at a constant $20 k m / h r$ and then pedals at a constant $40 k m / h r$ for another $15$ minutes?

27.5 k m / h r

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25 k m / h r

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22.5 k m / h r

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30 k m / h r

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32.5 k m / h r

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Solution

The correct option is A $27.5 k m / h r$
Distance traveled in 30 min $S_{1} = 25 \times 0.5 = 12.5$ $k m$
Distance traveled in mid 15 min $S_{2} = 20 \times \frac{15}{60} = 5$ $k m$

Distance traveled in last 15 min $S_{3} = 40 \times \frac{12}{60} = 10$ $k m$
Total distance traveled $S = 12.5 + 5 + 10 = 27.5$ $k m$
Total time taken $T = 1$ hr
$∴$ Average speed $= \frac{S}{T} = \frac{27.5}{1} = 27.5$ $k m / h r$

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What was the average speed of the cyclist for the past hour when he travels at a constant 25 km/hr for 30 minutes, coasts for 15 minutes at a constant 20 km/hr and then pedals at a constant 40 km/hr for another 15 minutes?

The correct option is A 27.5 km/hrDistance traveled in 30 min S1=25×0.5=12.5 kmDistance traveled in mid 15 min S2=20×1560=5 kmDistance traveled in last 15 min S3=40×1260=10 kmTotal distance traveled S=12.5+5+10=27.5 kmTotal time taken T=1 hr∴ Average speed =ST=27.51=27.5 km/hr

What was the average speed of the cyclist for the past hour when he travels at a constant $25 k m / h r$ for $30$ minutes, coasts for $15$ minutes at a constant $20 k m / h r$ and then pedals at a constant $40 k m / h r$ for another $15$ minutes?