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Question

What will be de Broglie wavelength of an electron moving with a velocity of 1.2×105ms1?

A
6.068×109m
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B
3.133×1037m
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C
6.626×109m
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D
6.018×107m
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Solution

The correct option is B 6.068×109m
λ=hmv
λ=6.62×10349.1×1031×1.2×105

λ=6.062×109m

option (A) is correct.

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