What will be the bond order stability magnetic character of $O_{2}^{+}, O_{2}^{-}$ and $N_{2}^{+}$ and $N_{2}^{2 -}$ ?

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Solution

Bond Order $= \frac{N o . o f b o n d i n g e l e c t r o n - N o . o f n o n - b o n d i n g e l e c t r o n}{2}$
Bond Order $\propto$ Stability
$O_{2}^{\oplus} \to B . O = 2.5 O_{2}^{⊖} \to B . O = 1.5 N_{2}^{\oplus} \to B . O = 2.5 N_{2}^{2 ⊖} \to B . O = 2$
Stability Oder $= N_{2}^{\oplus} \sim O_{2}^{\oplus} > O_{2}^{⊖} > N_{2}^{2 ⊖}$

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Calculate the total number of molecules that will possess fractional bond order among the following molecules
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and arrange in decreasing order of bond strength. Predict their magnetic character.

Q. Give the Molecular Orbital Energy diagram of a)

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O_{2}

molecules.

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is form

N_{2}

bond-order ......... and when

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is formed from

O_{2}

bond-order ........

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What will be the bond order stability magnetic character of O+2,O−2 and N+2 and N2−2?

Bond Order =No. of bonding electron−No. of non−bonding electron2Bond Order ∝ StabilityO⊕2→B.O=2.5O⊖2→B.O=1.5N⊕2→B.O=2.5N2⊖2→B.O=2Stability Oder=N⊕2∼O⊕2>O⊖2>N2⊖2

What will be the bond order stability magnetic character of $O_{2}^{+}, O_{2}^{-}$ and $N_{2}^{+}$ and $N_{2}^{2 -}$ ?