Question

What will be the change in the internal energy (in %) when a gas is cooled from 927° to 27°?

Answer 1

Answer:

T₁ = 927 + 273 = 1200 K

T₂ = 27 + 273 = 300 K

internal energy ∝ Temperature

U ∝ T

(U₁ / U₂) = (T₁ / T₂)

∴ [(U₁ – U₂) / U₂] = [(T₁ – T₂) / T₂]

∴ % change in energy = [{(1200 – 300) / (300)} × (100)]

= 3 × 100 = 300%