Question

What will be the maximum sum of 44, 42, 40, ......?

• A.
  502
• B.
  504
• C.
  506
• D.
  500

Answer 1

The correct option is C

506
For sum to be maximum, we will consider only positive terms

44 + 42 + ....... + 2

or 2 + 4 + 6 + ..... + 42 + 44

2[1 + 2 + 3 + ..... + 22]

$=\frac{2[22\times 23]}{2}=506$


Alternative Solution:

Sum of even Natural Numbers = n(n+1)

$\therefore$ We have series 2 + 4 + 6 + ..... + 44

So by putting values in formula:

= 22 $\times$ (22 + 1) = 506