What will be the minimum pressure required to compress 500 dm $^{3}$ of air at 1 bar to 200 dm $^{3}$ at 30 $^{0}$ C?

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Solution

We know, PV = P'V'
By putting all those values, we get-

The minimum pressure required to compress air is $P^{'} = \frac{P V}{V^{'}} = \frac{1 \times 500}{200} = 2.5 b a r$ .

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